Find the equation in terms of x of the line through (-3,1) and (3,0)

Answer:The answer to your question is:            y = -1/6 x + 1/2Step-by-step explanation:DataA (-3, 1)B (3, 0)Formula                m = (y2 - y1) / (x2 - x1)                y = mx + b                (y - y1) = m(x - x1)Process               m = (0 - 1) / (3 + 3)               m = -1 / 6              ( y - 1) = -1/6 (x + 3)               6 ( y - 1) = -1(x + 3)               6y - 6 = -x - 3               6y = - x - 3 + 6               6y = -x + 3               y = -1/6 x + 3/6               y = -1/6 x + 1/2               x + 6y -3 = 0               x = -6y + 3