How many solutions exist for the given equation? 1/2 x+12=4x-1 zero one two infinitely many
Accepted Solution
Answer:There's 1 solution.Solve for x by simplifying both sides of the equation, then isolating the variable.x=2Step-by-step explanation:1/2(x+12)=4x−1
Step 1: Simplify both sides of the equation.
1/2(x+12)=4x−1
(1/2)(x)+(1/2)(12)=4x+−1(Distribute)
1/2x+6=4x+−1
1/2x+6=4x−1
Step 2: Subtract 4x from both sides.
1/2x+6−4x=4x−1−4x
−7/2x+6=−1
Step 3: Subtract 6 from both sides.
−7/2x+6−6=−1−6
−7/2x=−7
Step 4: Multiply both sides by 2/(-7).
(2/−7)*(−7/2x)=(2/−7)*(−7)
x=2
Step 1: Simplify both sides of the equation.
1/2(x+12)=4x−1
(1/2)(x)+(1/2)(12)=4x+−1(Distribute)
1/2x+6=4x+−1
1/2x+6=4x−1
Step 2: Subtract 4x from both sides.
1/2x+6−4x=4x−1−4x
−7/2x+6=−1
Step 3: Subtract 6 from both sides.
−7/2x+6−6=−1−6
−7/2x=−7
Step 4: Multiply both sides by 2/(-7).
(2/−7)*(−7/2x)=(2/−7)*(−7)
x=2